最新CCNA考題
最新CCNA考題1.Which of the following are true concerning distance vector and link state routing protocols? (Choose 2.)
A. Distance vector protocols send the entire routing table to directly connected neighbors.
B. Link state protocols send the entire routing table to all routers in the network.
C. Distance vector protocols send updates about directly connected neighbors to all networks listed in the routing table.
D. Link state protocols send updates containing the state of their own links to all other routers on the network.
Answer:AD
最新CCNA考題2.Given a subnet mask of 255.255.255.224, which of the following addresses can be assigned to network hosts? (Choose three.)
A. 15.234.118.63
B. 92.11.178.93
C. 134.178.18.56
D. 192.168.16.87
E. 201.45.116.159
F. 217.63.12.192
Answer:BCD
解釋?zhuān)?224 11100000 3位表示網(wǎng)絡(luò)， 5位代表主機(jī)
A. 15.234.118.63 63 二進(jìn)制為： 111111 為廣播地址
B. 92.11.178.93 93 二進(jìn)制為： 1011101 可以使用
C. 134.178.18.56 56 二進(jìn)制為： 111000 可以使用
D. 192.168.16.87 87 二進(jìn)制為： 1010111 可以使用
E. 201.45.116.159 159 二進(jìn)制為：10011111 為廣播地址
F. 217.63.12.192 192 二進(jìn)制為：11000000 代表網(wǎng)絡(luò)
最新CCNA考題3.Refer to the graphic.
 |
The network administrator suspects that the link is overloaded. Based on the partial output of the
Router# show frame relay pvc
command shown in the graphic, which output value indicates to the local router that traffic sent to the corporate site is experiencing congestion?
A. DLCI=100
B. last time PVC status changed 00:25:40
C. in BECN packets 192
D. in FECN packets 147
E. in DE packets 0
Answer:C
解釋?zhuān)?/P>
BECN為后向擁塞指示：
FECN為前向擁塞指示：
BECN是向數(shù)據(jù)傳輸方向的源方發(fā)送的（方向與數(shù)據(jù)傳輸方向相反），
而FECN是向數(shù)據(jù)傳輸方向的目的方發(fā)送的（方向與數(shù)據(jù)傳輸方向相同）
此處in BECN packets 192，表示本地路由器發(fā)送數(shù)據(jù)到總部網(wǎng)絡(luò)時(shí)發(fā)生擁塞，
它收到BECN后，將會(huì)降低發(fā)送速率，從而導(dǎo)致速率下降。
選擇選擇 C
最新CCNA考題5.
 |
Upon reviewing the command output of both routers, what is the most likely cause of the problem?
A. Authentication needs to be changed to PAP for both routers.
B. Serial ip addresses of routers are not on the same subnet.
C. Username/password is incorrectly configured.
D. Router names are incorrectly configured.
Answer:C
解釋?zhuān)?由圖看出 密碼配置有錯(cuò)誤， 一個(gè)是 cisco ,一個(gè)是 cisco1
#p#
最新CCNA考題6.
 |
networking problem and the protocol or setting that should be used to prevent the problem?
A. routing loops, hold down timers
B. switching loops, split horizon
C. routing loops, split horizon
D. switching loops, VTP
E. routing loops, STP
F. switching loops, STP
Answer:F
解釋?zhuān)簣D中看出，是一交換機(jī)互連的有冗余連接的網(wǎng)絡(luò)，
routing loops, hold down timers ,split horizon 這里都是路由網(wǎng)絡(luò)中的一些概念
冗余連接的交換網(wǎng)絡(luò)，
會(huì)出現(xiàn)： 交換環(huán)路 switching loops
解決方法： STP 生成樹(shù) 協(xié)議
最新CCNA考題7.Assuming that a router contains both physical and logical interfaces,
what factor determines the OSPF router ID?
A. the lowest network number of any interface
B. the lowest IP address of any logical interface
C. the lowest IP address of any physical interface
D. the highest network number of any interface
E. the highest IP address of any logical interface
F. the highest IP address of any physical interface
Answer:E
解釋?zhuān)?E is ok! 這也是我們?cè)谂渲肙SPF 路由的時(shí)候， 為了保證路由的穩(wěn)定， 一般都會(huì)配置LOOPBACK 接口
WHY? LOOPBACK 接口 就是logical interface ， logical interface 為永遠(yuǎn) UP 。
最新CCNA考題8.
 |
A. Host 1 - 192.168.10.22/24; Host 2 - 192.168.10.23/24; Host 3 - 192.168.10.24/24
B. Host 1 - 192.168.10.22/24; Host 2 - 192.168.11.23/24; Host 3 - 192.168.10.23/24
C. Host 1 - 192.168.10.22/24; Host 2 - 192.168.10.23/24; Host 3 - 192.168.11.23/24
D. Host 1 - 192.168.11.22/24; Host 2 - 192.168.11.23/24; Host 3 - 192.168.10.24/24
Answer:B
解釋?zhuān)好總€(gè)VLAN 分別為一個(gè) 網(wǎng)段， 所以Host1, Host3 在同一網(wǎng)段， Host2 應(yīng)該在其他的一個(gè)不同的網(wǎng)段
最新CCNA考題9.
 |
Which single access list statement will combine all four of these statements
into a single statement that will have exactly the same effect?
A. access-list 10 permit 172.29.16.0 0.0.0.255
B. access-list 10 permit 172.29.16.0 0.0.1.255
C. access-list 10 permit 172.29.16.0 0.0.3.255
D. access-list 10 permit 172.29.16.0 0.0.15.255
E. access-list 10 permit 172.29.0.0 0.0.255.255
Answer:C
解釋 : 0.0.3.255 表示第3部分， 最后2位可變: 分別為：
00 (0) ＋ 16 代表了16
01 (1) ＋ 16 代表了17
10 (2) ＋ 16 代表了18
11 (3) ＋ 16 代表了19
最新CCNA考題10.
 |
Refer to the graphic. A host is connected to switch port Fa0/3 with a crossover cable.
The host and switch have been fully configured for IP connectivity as shown.
However, the port indicator on switch port Fa0/3 is not on,
and the host can not communicate with any other hosts including those connected to VLAN 2 on the same switch.
Based on the information given, what is the problem?
A. Switch port Fa0/3 is not configured as a trunk port.
B. The cable is the wrong type.
C. The switch has been assigned an incorrect subnet mask.
D. Switch port Fa0/3 has been blocked by STP.
E. The switch and the hosts must be in the same subnet.
Answer:B
解釋 : PC與交換機(jī) 互連應(yīng)該使用直通線
PC與PC, PC與路由器，路由器ETHERNET 與路由器ETHERNET ， 互連才需要使用crossover cable。
這就是十道最新CCNA考題。
【編輯推薦】
