MySQL學(xué)習(xí):GROUP BY分組取最新的一條記錄
日常開發(fā)當(dāng)中,經(jīng)常會(huì)遇到查詢分組數(shù)據(jù)中最新的一條記錄,比如統(tǒng)計(jì)當(dāng)前系統(tǒng)每個(gè)人的最新登錄記錄、外賣系統(tǒng)統(tǒng)計(jì)所有買家最新的一次訂單記錄、圖書管理系統(tǒng)借閱者最新借閱書籍的記錄等等。今天給大家介紹一下如何實(shí)現(xiàn)以上場(chǎng)景的SQL寫法,希望對(duì)大家能有所幫助!
1、初始化數(shù)據(jù)表
- -- 借閱者表
- CREATE TABLE `userinfo` (
- `uid` int(11) NOT NULL AUTO_INCREMENT COMMENT '主鍵',
- `uname` varchar(20) NOT NULL COMMENT '姓名',
- `uage` int(11) NOT NULL COMMENT '年齡',
- PRIMARY KEY (`uid`) USING BTREE
- ) ENGINE=InnoDB AUTO_INCREMENT=8 DEFAULT CHARSET=utf8 ROW_FORMAT=COMPACT;
- INSERT INTO `userinfo` VALUES (1, '小明', 20);
- INSERT INTO `userinfo` VALUES (2, '小張', 30);
- INSERT INTO `userinfo` VALUES (3, '小李', 28);
- -- 書籍表
- CREATE TABLE `bookinfo` (
- `id` int(11) NOT NULL AUTO_INCREMENT COMMENT '主鍵',
- `book_no` varchar(20) NOT NULL COMMENT '書籍編號(hào)',
- `book_name` varchar(20) NOT NULL COMMENT '書籍名稱',
- PRIMARY KEY (`id`) USING BTREE
- ) ENGINE=InnoDB AUTO_INCREMENT=14 DEFAULT CHARSET=utf8 ROW_FORMAT=COMPACT;
- INSERT INTO `bookinfo` VALUES (1, 'ISBN001', '計(jì)算機(jī)基礎(chǔ)');
- INSERT INTO `bookinfo` VALUES (2, 'ISBN002', '計(jì)算機(jī)網(wǎng)絡(luò)');
- INSERT INTO `bookinfo` VALUES (3, 'ISBN003', '高等數(shù)學(xué)');
- INSERT INTO `bookinfo` VALUES (4, 'ISBN004', '明朝那些事');
- INSERT INTO `bookinfo` VALUES (5, 'ISBN005', '物理');
- INSERT INTO `bookinfo` VALUES (13, 'ISBN006', '讀者');
- -- 借閱記錄表
- CREATE TABLE `borrow_record` (
- `id` int(11) NOT NULL AUTO_INCREMENT COMMENT '主鍵',
- `user_id` int(11) NOT NULL COMMENT '用戶id',
- `book_id` int(11) NOT NULL COMMENT '書籍id',
- `borrowtime` datetime NOT NULL COMMENT '書籍id',
- PRIMARY KEY (`id`) USING BTREE
- ) ENGINE=InnoDB AUTO_INCREMENT=16 DEFAULT CHARSET=utf8 ROW_FORMAT=COMPACT;
- INSERT INTO `borrow_record` VALUES (8, 1, 2, '2021-05-01 10:52:00');
- INSERT INTO `borrow_record` VALUES (9, 2, 4, '2021-07-12 23:32:00');
- INSERT INTO `borrow_record` VALUES (10, 2, 1, '2021-03-21 09:00:00');
- INSERT INTO `borrow_record` VALUES (11, 1, 3, '2021-08-11 17:39:00');
- INSERT INTO `borrow_record` VALUES (12, 1, 5, '2021-09-02 18:12:00');
- INSERT INTO `borrow_record` VALUES (13, 3, 1, '2021-07-06 12:32:00');
- INSERT INTO `borrow_record` VALUES (14, 2, 1, '2021-08-09 10:10:00');
- INSERT INTO `borrow_record` VALUES (15, 4, 3, '2021-04-15 19:45:00'
寫法1 直接group by 根據(jù)userid ,使用聚合函數(shù)max取得最近的瀏覽時(shí)間
- select a.user_id ,max(c.uname) uname
- ,max(a.borrowtime) borrowtime,max(b.book_name) book_name
- from borrow_record a
- INNER JOIN bookinfo b on b.id=a.book_id
- INNER JOIN userinfo c on c.uid=a.user_id
- GROUP BY a.user_id
- -- 說明: 這樣會(huì)存在獲取書籍名稱錯(cuò)亂的情況,
- -- 因?yàn)槭褂镁酆虾瘮?shù)獲取的書籍名稱,不一定是對(duì)應(yīng)用戶
- -- 最新瀏覽記錄對(duì)應(yīng)的書籍名稱
寫法2 采用子查詢的方式,獲取借閱記錄表最近的瀏覽時(shí)間作為查詢條件
- select a.user_id ,c.uname,a.borrowtime
- ,b.book_name book_namefrom borrow_record a
- INNER JOIN bookinfo b on b.id=a.book_id
- INNER JOIN userinfo c on c.uid=a.user_id
- where a.borrowtime=(select max(borrowtime)
- from borrow_record t where t.user_id=a.user_id)
- -- 說明:可以滿足查詢效果,不過性能不是最優(yōu)解
寫法3 采用group by + join 性能最高,推薦采用
- select a.user_id ,c.uname,a.borrowtime
- ,b.book_name book_namefrom (
- select t.user_id,max(borrowtime) borrowtime
- from borrow_record t GROUP BY t.user_id) as e
- INNER JOIN borrow_record a on e.user_id=a.user_id
- and e.borrowtime=a.borrowtimeINNER
- JOIN bookinfo b on b.id=a.book_id
- INNER JOIN userinfo c on c.uid=a.user_id
運(yùn)行效果如下: